17%
12.09.2013
Companies that want to integrate their users' smartphones into their existing infrastructure can do so with various Microsoft products. One example is System Center Configuration Manager (SCCM) 2012
17%
09.04.2019
first beta release in 2012, these qualities have attracted a growing community of numerical scientists to the young language. Naturally, Julia love is not unanimous, but the general agreement
17%
19.06.2013
..
Figure 1: CPU clock frequency over time (CC BY-SA 3.0 US).
Of course, you know the reason: Higher clocks, and thus temperatures, were not sustainable. That is not to say clock rates will not increase
17%
20.08.2012
the port after the file transfer has completed (but not without moving to the netcat-traditional
package, as mentioned before):
{ echo -ne "HTTP/1.0 200 OK\r\n\r\n"; cat filename.tar.gz; } | nc -l -p 15000
17%
13.02.2017
for installation of certain Windows features.
Listing a computer's group memberships.
Entering DNS servers.
I am using Windows 10 client with a Windows Server 2012 R2 domain, with PowerShell v5
17%
26.01.2025
as a new language [4] for scientific and technical computing. Since its relatively recent public release in 2012, its unique melding of advanced concepts in language design with uncompromised performance has
17%
01.06.2024
Kerberoasting right at the source, although you will very rarely see it used in production environments. With the authentication policies introduced in Windows Server 2012 R2, you can specify which accounts
17%
07.07.2015
Mark Cox of the OpenSSL project team has announced a pending OpenSSL release. Versions 1.0.2d and 1.0.1p will appear on July 9. The brief letter on the OpenSSL list says the update will fix
17%
04.12.2024
the attack surface can be enabled on Windows Server from version 2012 and Windows 10 and work without the Defender portal or group policies, even on home computers (more on this later). Armed with Defender
17%
05.12.2019
before moving to the next column.
Listing 1
row.c
#include
#define SIZE 10000
**
int array[SIZE][SIZE] = {0};
int main() {
for (int i = 0; i < SIZE; i++)
for (int j
