17%
06.10.2019
constraint:
requires maxRead(argv[1] @ example1.c:8:20) <= 9
needed to satisfy precondition:
requires maxSet(buffer @ example1.c:8:12) >= maxRead(argv[1] @
example1.c:8:20)
derived from
17%
07.01.2014
of space (20 + 25 + 30), with no doubt lots of duplicated data wasting space and money.
The backup world uses a few techniques that differentiate it from replication. The first is called a “full backup
17%
30.11.2025
check_interval 5
12 retry_interval 1
13 contacts spz_admin
14 notification_period 24x7
15
17%
30.01.2020
Fn::Base64:
20 Fn::Join:
21 - ''
22 -
23 - "{\n"
24 - '"bucket"'
25 - ' : "'
26 - Ref: S3Bucketname
27
17%
07.11.2011
if '__main__' == __name__:
12
13 p1 = Process(target = count, args = (20, ' Rich',))
14 p2 = Process(target = count, args = (25, ' Nus',))
15 p3 = Process(target = count, args = (30, ' Geeks
17%
30.11.2025
(number, label):
07 for i in xrange(number):
08 print ' ' + str(i) + ' ' + label
09 sleep((number - 15)/10.0)
10
11 if '__main__' == __name__:
12
13 p1 = Process(target = count, args = (20
17%
20.06.2012
:2:root,bin,daemon
sys:x:3:root,bin,adm
adm:x:4:root,adm,daemon
tty:x:5:
disk:x:6:root
lp:x:7:daemon,lp
mem:x:8:
kmem:x:9:
wheel:x:10:root
mail:x:12:mail,postfix
uucp:x:14:uucp
man:x:15:
games:x:20
17%
31.07.2013
Code Example
1 #include
2
3 /* Our structure */
4 struct rec
5 {
6 int x,y,z;
7 float value;
8 };
9
10 int main()
11 {
12 int counter;
13 struct rec my
17%
11.10.2016
straightforward. If a processor was operating at a fixed frequency of 2.0GHz, CPU utilization was the percentage of time the processor spent doing work. (Not doing work is idle
time.) For 50% utilization
17%
30.11.2025
c/s virtual
12
13 Benchmarking: OpenBSD Blowfish (x32) [32/64 X2]... DONE
14 Raw: 723 c/s real, 723 c/s virtual
15
16 Benchmarking: Kerberos AFS DES [48/64 4K]... DONE
17 Short: 378501 c/s real
