16%
20.02.2012
.51, 0, 0.36, 17.74, 0.00, 6.38, 90, 0
2012-01-09 21:10:00, 92, 4.42, 0, 0.35, 20.81, 0.00, 7.22, 100, 0
2012-01-09 21
15%
23.03.2022
laytonjb laytonjb 19946519 Nov 20 2020 Lmod-8.4.15.tar.gz
31988342 drwxrwxr-x 2 laytonjb laytonjb 4096 Oct 27 14:22 mpibzip2-0.6
31988329 -rw-rw-r-- 1 laytonjb laytonjb 92160 Oct 27 14:18 mpibzip
15%
09.08.2015
/956026386
Cobie Smulders - Maria Hill 23514560145
Hugh jackman - Wolverine 801539193
Paul Rudd - Ant Man 497349000
Listing 2
testlist.txt
22 April 1984
7.04.1985
30 March 1986
19 April 1987
03
15%
09.04.2019
=> this.addItem());
19 this.listItem().forEach(text => this.showItem(text));
20 }
21
22 addItem() {
23 let text = this.shadowRoot.querySelector('#text').value;
24 if (!this
15%
17.02.2015
for x in rep.df.rx2(2)])
17
18 devs.png(file=path, width=512, height=512)
19 ro.r.plot(x_vals, y_vals, xlab=x_lab, ylab=y_lab, main=main)
20 devs.dev_off()
21
22 rep
15%
18.07.2013
proxy_intercept_errors on;
17 ...
18 Filming location
19 ...
20 error_page 502 @ fallback;
21 proxy_next_upstream HTTP_500 http_502 http_503 http_504 timeout error invalid_header;
22 proxy_pass http
15%
30.11.2020
, this code should make sense.
Listing 7
Parallel Trapezoid Method
01 from mpi4py import MPI
02 import math
03
04
05 def f(x):
06 return x*x
07 # end def
08
09
10 def trapezoidal(a, b, n, h
15%
07.11.2011
print str(id) + ' Total waste of CPU cycles!'
08
09 if '__main__' == __name__:
10
11 for i in xrange(20):
12 Process(target = waste, args = (i,)).start()
The counting.py
program delays
15%
10.04.2015
]
20 }
21 ]
22 }
23 ]
24 }
The script that performs the rsync operation, sync.sh, will look like Listing 3. Your script might be more complex (e.g., by adding some sort
15%
01.06.2024
is 20x because only 95 percent of the algorithm can execute in parallel (compute the fraction 1/20 from that 5% number). That limitation led to a search for embarrassingly parallel
algorithms
