17%
21.08.2012
.6 M
Is this ok [y/N]: y
Downloading Packages:
(1/5): apr-1.3.9-3.el6_1.2.i686.rpm | 128 kB 00:00
(2/5): expat-2.0.1-11.el6_2.i686.rpm
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19.09.2019
= np.array([10, 20, 30, 40])
print('a+b:\n', add_ufunc(a, b))
The answer should be:
a+b:
[11 22 33 44]
In the previous example, you had to put everything that was to run on the GPU into a single Numba
17%
10.10.2012
tmp DISPATCH_WINDOW # Keywords
test1 0 () () () () () ()
n0001 3 () () () () () ()
default
17%
03.12.2015
is over and done with as soon as the message is delivered. MQTT enables a decoupled 1-to-n
or 1-to-1 relationship between different devices or programs that do not specifically need to know each other
17%
29.09.2020
-system svclb-traefik-p46m5 2/2 Running 0 11m
kube-system coredns-d798c9dd-kjhjv 1/1 Running 0 12m
kube-system traefik-6787cddb4b-594
17%
13.12.2018
"$file" ]; then
05 touch /tmp/listner.log
06 fi
07 tail -n 0 -F /db/oraclese/product/diag/tnslsnr/pics-db11/listener/trace/listener.log | while read LINE
08 do
09 echo "\"host:\" "\"picsdb\", \"message
17%
07.02.2019
data copy(a)
!$acc parallel loop
do i=1,n
a(i) = 0.0
enddo
!$acc data end
#pragma acc data copy(a)
{
#pragma acc parallel loop
{
for (int i=0; i < n; i++)
{
a[i] = 0.0
17%
05.12.2019
main() {
int *p = a;
for(int i=0; i < 20; i++)
printf("%d, ", *p++);
printf("\b\b \n"); // erasing the trailing comma and adding a newline
return 0;
}
Running the third
17%
17.12.2014
.6%, with the remaining 0.4% devoted to system time.
On the right-hand side of the display is an ASCII chart of CPU percentages for each core, with the legend running along the top of the chart. User time is shown with U
17%
06.10.2019
.
21 #
22 [registries.block]
23 registries = []
These registries are called when Podman can't find an image locally or if an image doesn't contain a fully qualified registry name within an image
