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30.01.2024
:
- "main"
jobs:
build:
runs-on: ubuntu:22.04
steps:
-
name: Checkout
uses: actions/checkout@v3
-
name: Login to Docker Hub
uses: docker/login-action@v2
with:
username
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03.12.2024
.9.0. The TensorFlow version is a bit old; 2.16.1 is the latest as of this writing, but I already had it installed. My Keras is also a bit old. I think Keras 3.6 is the latest, and my version isn't even 3.x. I haven
17%
26.01.2025
Flow 2.9.2 and Keras 2.9.0. The TensorFlow version is a bit old; 2.16.1 is the latest as of this writing, but I already had it installed. My Keras is also a bit old. I think Keras 3.6 is the latest, and my
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25.09.2023
guest
82a84,88
>
> tee /etc/.htpasswd <<'EOF'
> guest:$apr1$gz4n7s6o$P.O/V1k9rZuV9nN/5lh3l0
> admin:$apr1$esczj7wu$ffu/6j8vETMAMJaVTKn7a1
> EOF
Monit is configured to load service
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20.08.2012
examplehost.tld 22
If firewalling is in place and you need to originate your connection from a specific IP address to open a port, entering
# nc -s 1.2.3.4 examplehost.tld 8181
will connect to examplhost
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25.01.2022
to get into the Linux kernel. A couple of my earlier articles that mention FUSE address data encryption and working with S3QL object storage. As evident by these applications, FUSE can be very useful
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11.06.2014
on the Rex host and then copy the public key over to the client (Listing 3). After that, a test login on the client without password should work.
Listing 3
Key-Based Authentication
01 root
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31.10.2025
seconds, for example:
# nc -p 16000 -w 30 examplehost.tld 22
If firewalling is in place and you need to originate your connection from a specific IP address to open a port, then you can enter:
# nc -s 1.2.3
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18.09.2012
2 apache2-mpm-prefork apache2-utils apache2.2-bin \
apache2.2-common apache2-doc apache2-suexec libapache2-mod-php5 libapr1 \
libaprutil1 libaprutil1-dbd-sqlite3 libaprutil1-ldap libapr1
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17.08.2011
hour.
The script simply connects to AWS, finds each of the main chargeable services (I’ve only done EC2, RDS, and S3 so far … feel free to contribute), and uses a table of costs to find the upper limit
