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": executable file not found in $PATH 0a2091b63bc5de710238fadc68ba3f5e0f9af8800ec7f76fd52a84c49a1ab0a7 Listing 3 shows that I do have a working container, so I'll deal with the network namespace error now

is considered "embarrassingly parallel" [3] where no design effort is required to partition the problem into completely separate parts. If no data dependency exists between the problem sub-parts, no communication

-east-1d Keypair: foocluster EBS volumes:     vol-4c048437 on master:/dev/sda (status: attached)     vol-4f048434 on node001:/dev/sda (status: attached) Cluster nodes:     master running i-6a10c710 ec2

3 04 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 05 +-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+ 06 | Source Port

/json;charset=utf-8\n\r\n\r%s" %json.dumps(obj) Lines 9 through 18 iterate against all entries of a database cursor, which the call to the find() method in line 9, generates from the queried data collection

,1000); 06 07 // Set host data on the Device (GPU) 08 dA = gpuSetData(A); 09 dC = gpuSetData(C); 10 11 d1 = gpuMult(A,B); 12 d2 = gpuMult(dA,dC); 13 d3 = gpuMult(d1,d2); 14 result = gpuGetData(d3); // Get

You ha ve parallelized your serial application ,  but as you use more cores you are  n o t seeing any improvement  in performance . What gives? ... the asymptote is the inverse of the serial portion of the code, which controls the scalability of the application . In this example, p = 0.8 and (1 – p ) = 0.2, so the asymptotic value is a = 5. Further ... You  ha ve parallelized your serial application ,  but as you use more cores you are  n o t seeing any improvement  in performance . What gives?

#, Objective-C, Lua, Perl, and Python. The subscriber written in Python initially arranges a callback to be invoked when a message arrives (Listing 3). Listing 3 Subscriber in Python 01 #!/usr

than a single variable/value pair can be passed, à la: cdk -c VAR1=value1 -c VAR2=value2 This mechanism provides a great deal of power and flexibility, particularly when considering the use of CDK

a : Notice that the denominator is now a function of n 2. From Equation 8 you can plot the speedup. As with the previous problem, assume a parallel portion p = 0.8, leaving a serial portion s = 0