struct jail
01 main(int argc, char **argv)
02 {
03 struct jail j;
04 int i;
05 [...]
06 /* Populate the jail struct */
07 memset(&j, 0, sizeof(j));
08 j.version = 0;
09 j.path =
24%
20.10.2013
: Z1F35P0G
LU WWN Device Id: 5 000c50 050b954c3
Firmware Version: CC27
User Capacity: 3,000,592,982,016 bytes [3.00 TB]
Sector Sizes: 512 bytes logical, 4096 bytes physical
Device is: In smartctl
24%
19.10.2012
is US$ 3.1/hour.
Thus, using the small usage case (80 cores, 4GB of RAM per core, and basic storage of 500GB) would cost US$ 24.00/hour (10 Eight Extra Large Instances). The larger usage case (256 cores