20%
02.08.2021
---------------- -------------------- ---------------------------------------- --------- -------------------------- ---------------- --------
/dev/nvme0n1 S3ESNX0JA48075E Samsung SSD 960 EVO 250GB 1 22.41 GB / 250.06 GB 512 B + 0 B 2B7QCXE7
/dev/nvme1n1 07b4753784e26c18 Linux
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13.12.2022
-export-libs-9.11.36-3.el8_6.1.x86_64.rpm 579 kB/s | 1.1 MB 00:02
(6/6): warewulf-4.3.0-1.git_235c23c.el8.x86_64.rpm 746 kB/s | 8.3 MB 00
20%
11.05.2021
, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192]
A = single( rand(N,N) );
B = single( rand(N,N) );
start = clock();
C = A*B;
elapsedTime = etime(clock(), start);
gFlops = 2*N*N*N / (elapsedTime * 1e+9);
disp(sprintf("N = %4d
20%
21.08.2012
.1 M
Total download size: 3.9 M
Installed size: 18 M
Is this ok [y/N]: y
Downloading Packages:
(1/4): php-5.3.3-14.el6_3.x86_64.rpm | 1.1 MB 00:00
(2/4): php-cli-5.3.3
20%
09.08.2015
-n
Show version
-v
Table 3
Editing Commands
Action
Command
Add lines above this one
i
Add lines below this one
20%
30.11.2020
):
11
12 s = 0.0
13 s += h * f(a)
14 for i in range(1, n):
15 s += 2.0 * h * f(a + i*h)
16 # end for
17 s += h * f(b)
18 return (s/2.)
19 # end def
20
21
22 # Main section
23 comm = MPI
19%
17.06.2017
-1) = 0.25 * (a(1:n-2,2:n) + a(3:n,2:n) + a(2:n,1:n-2) + a(2:n,3:n))
Using forall, the same can be written as:
forall (i=2:n-1, j=2:n-1) a(i,j) = 0.25*(a(i-1,j) + a(i+1,j) + a(i,j-1) + a(i,j+1
19%
11.04.2016
B blocks: 25.3 IO/s, 50.6 MiB/s (424.9 Mbit/s)
As the block size continues to grow, the transfer rate becomes increasingly important; a track change is only possible after fully reading the current
19%
02.06.2020
cddaa6-0886-44b3-9590-16717d5cd3c2",
20 "service_instance_guid": null,
21 "port": null,
22 "domain_url": "/v2/shared_domains/fb6bd89f-2ed9-49d4-9ad1-97951a573135",
23
19%
07.10.2014
276 MB 2.5 GB 2014-03-10 19:49 982a3c 2
# dog vdi tree
ntestvm1.img---[2014-02-05 15:04]---[2014-03-01 11:42]---[2014-03-10 19:48]---(you are here)
#
# qemu-img snapshot -l sheepdog:192
