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05.12.2019
).
Figure 1: Flattening a 2D array in C or C++.
Listing 3
inspect.c
#include
**
int a[4][5] = { // array of 4 arrays of 5 ints each, a 4x5 matrix
{ 1, 2, 3
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07.06.2019
sha256:f1ca87d9adb678b180c31bf21eb9798b043c22571f419ed844bca1d103f2a2f7 bf85f2b6bf52 13 months ago 15.5MB
The output shows information on both the original nginx:alpine image and the updated
49%
11.04.2016
toolkit for joomla
UrlToolkit {
ToolkitID = joomla
Match base64_encode[^(]*\([^)]*\) DenyAccess
Match (<|%3C)([^s]*s)+cript.*(>|%3E) DenyAccess
Match GLOBALS(=|\[|\%[0-9A-Z]{0,2}) Deny
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16.01.2013
$ starcluster start -s 1 foocluster -n ami-999d49f0
$ starcluster get foocluster /opt/sge6-fresh .
$ starcluster terminate foocluster
$ starcluster start -o -s 1 -i t1.micro -n ami-e2a0058b imagehost
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22.12.2017
in cs us sy id wa st
04 1 0 0 5279852 2256 668972 0 0 1724 25 965 1042 17 9 71 2 0
05 1 0 0 5269008 2256 669004 0 0 0 0 2667 1679 28 3 69 0 0
06 1 0
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09.01.2019
of the loop, n
, is large enough, some processing hardware can greatly speed up the computation.
What happens if z(i)
depends on a previous value, as in the following:
do i = 2,n
z(i) = z(i-1)*2
enddo
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04.08.2020
(minified by 25.99X)
from python:2.7-alpine - 84.3MB => 23.1MB (minified by 3.65X)
from python:2.7.15 - 916MB => 27.5MB (minified by 33.29X)
from centos:7 - 647MB => 23MB (minified by 28.57X)
from centos
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07.03.2019
; you should collapse two or more loops.
Table 4: Collapsing Loops
Fortran
C
!$acc parallel loop collapse(2)
do i=1,n
...
do j=1,m
...
enddo
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02.02.2021
from 1.00 with one processor to 1.67 with two processors. Although not quite a doubling in performance (a
would have to be 2), about one-third of the possible performance was lost because of the serial
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24.02.2022
MB
p
s
or Peak IOPS is
x
. However, what does “IOPS” really mean and how is it defined?
Typically, an IOP is an I/O operation, wherein data is either read or written to the filesystem
