15%
18.02.2018
.e., in this example).
If the MySQL version you are using is version 5.5.3 or newer, then replace utf8 with utf8mb4:
DATABASE_ENCODING=utf8mb4
The results should look like Figure 1. At the bottom
15%
10.04.2015
Qualys SSL-Test A+
Qualys SSL-Test A
Syss GmbH
Audits [2]
TLS 1.2
Yes
Yes
Yes
Yes
HTTPS/HSTS
Yes
Yes
Yes
Yes
15%
16.05.2013
,1000);
06
07 // Set host data on the Device (GPU)
08 dA = gpuSetData(A);
09 dC = gpuSetData(C);
10
11 d1 = gpuMult(A,B);
12 d2 = gpuMult(dA,dC);
13 d3 = gpuMult(d1,d2);
14 result = gpuGetData(d3); // Get
15%
14.03.2013
is a classic bug in a web application: an SQL injection vulnerability. SQL injection, which has been known for around 12 years, is still one of the hacker's most popular tools.
This article presents real
15%
19.02.2013
OSPF
01 !
02 hostname linuxrouter
03 password 8 7kdoaul4.iSTg
04 enable password 8 ZDF339a.20a3E
05 log file /var/log/quagga/zebra.log
06 service password-encryption
07 !
08 interface eth0
09 multicast
15%
17.12.2014
to see what might be causing the load.
Figure 8: Disk stats and top processes.
One last option I want to cover is n
, for network stats. Figure 9
15%
07.03.2019
acc parallel loop
{
for (j=0; j < m; j++) {
...
}
}
...
}
}
Table 3: Single-Directive Nested Loop
Fortran
C
!$acc parallel loop
do i=1,n
...
do
15%
05.02.2019
if z(i) depends on a previous value, as in the following:
do i = 2,n
z(i) = z(i-1)*2
enddo
As written, you can't generally parallelize the loop because of data dependency [4]. This dependency
15%
30.01.2020
of code.
Listing 1
Time to Execute
import time
start_time = time.time()
# Code to check follows
a, b = 1,2
c = a + b
# Code to check ends
end_time = time.time()
time_taken = (end_time- start
15%
18.03.2013
is a classic bug in a web application: an SQL injection vulnerability. SQL injection, which has been known for around 12 years, is still one of the hacker’s most popular tools.
This article presents real
