12%
10.10.2012
.
The output (if any) follows:
host name: n0001
host name: n0001
Running on host n0001
Start Time is Mon Sep 24 20:25:55 EDT 2012
Directory is /home/laytonjb/TEST_OPENLAVA
Using 2 processors across 1 nodes
12%
30.11.2025
=> 12;
05
06 # Hash AV pairs: (load in vusers, throughput in gets/sec)
07 %tpdata = ( (1,24), (2,48), (4,85), (7,100), (10,99), (20,94) );
08
09 @vusers = keys(%tpdata);
10 $model = "e-Commerce Final
12%
06.10.2019
constraint:
requires maxRead(argv[1] @ example1.c:8:20) <= 9
needed to satisfy precondition:
requires maxSet(buffer @ example1.c:8:12) >= maxRead(argv[1] @
example1.c:8:20)
derived from
12%
07.01.2014
of space (20 + 25 + 30), with no doubt lots of duplicated data wasting space and money.
The backup world uses a few techniques that differentiate it from replication. The first is called a “full backup
12%
30.11.2025
check_interval 5
12 retry_interval 1
13 contacts spz_admin
14 notification_period 24x7
15
12%
07.11.2011
if '__main__' == __name__:
12
13 p1 = Process(target = count, args = (20, ' Rich',))
14 p2 = Process(target = count, args = (25, ' Nus',))
15 p3 = Process(target = count, args = (30, ' Geeks
12%
30.11.2025
(number, label):
07 for i in xrange(number):
08 print ' ' + str(i) + ' ' + label
09 sleep((number - 15)/10.0)
10
11 if '__main__' == __name__:
12
13 p1 = Process(target = count, args = (20
12%
31.07.2013
Code Example
1 #include
2
3 /* Our structure */
4 struct rec
5 {
6 int x,y,z;
7 float value;
8 };
9
10 int main()
11 {
12 int counter;
13 struct rec my
12%
11.10.2016
straightforward. If a processor was operating at a fixed frequency of 2.0GHz, CPU utilization was the percentage of time the processor spent doing work. (Not doing work is idle
time.) For 50% utilization
12%
30.11.2025
c/s virtual
12
13 Benchmarking: OpenBSD Blowfish (x32) [32/64 X2]... DONE
14 Raw: 723 c/s real, 723 c/s virtual
15
16 Benchmarking: Kerberos AFS DES [48/64 4K]... DONE
17 Short: 378501 c/s real
