48%
14.08.2020
_age Always - 30
195 ECC_Error_Rate 0x001a 200 200 000 Old_age Always - 0
199 CRC_Error_Count 0x003e 100 100 000 Old_age Always - 0
235 POR
48%
12.05.2014
The revelation of wide-spread government snooping has sparked a renewed interest in data storage security via encryption. In this article, we review some options for encrypting files, directories ... recipient versus people who get access that information and try to break the encryption (decrypt it). There are literally hundreds of books on the subject (a quick Amazon search turned up 3,998 results ...
The revelation of wide-spread government snooping has sparked a renewed interest in data storage security via encryption. In this article, we review some options for encrypting files, directories
48%
29.09.2020
S.M.A.R.T. (Self-Monitoring, Analysis, and Reporting Technology) is a monitoring system for storage devices that provides information about the status of a device and allows for the running of self
48%
20.02.2012
time: 11.79 secs
Data transferred: 2.47 MB
Response time: 0.22 secs
Transaction rate: 35.79 trans/sec
Throughput: 0
48%
05.02.2019
of Listing 1, schemaVersion: "2.0.0" reveals that the test descriptions that follow use the 2.0.0 schema. Without this information, the tool immediately denies service.
Under globalEnvVars (lines 3-7; note
48%
14.03.2013
wrote this article I have started running test applications as Platform-as-a-Service apps in OpenShift [3]. OpenShift now also has a cartridge that lets you install MongoDB as an add-on. If you
48%
30.01.2020
| 0| 0.00%| # Compute the kinetic energy
202| 50| 0.000184059| 3.68118e-06| 0.00%| kinetic = 0.0
203| 200| 0.000753641| 3.76821e-06| 0.00%| for k in range(0, d
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17.09.2013
of an uncorrectable error by factors of 9–400.
Uncorrectable errors following a correctable error are still small at 0.1%–2.3% per year.
The incidence of correctable errors increases with age
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09.01.2019
3: Gang Execution
Fortran
C
!$acc parallel
do i=1,n
! do something
enddo
!$acc end parallel
#pragma acc parallel
{
for (int i=0; i < n
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13.10.2020
You ha
ve parallelized your serial application
,
but as you use more cores you are
n
o
t seeing any improvement
in performance
. What gives?
... and increasing the wall clock time.
Notice that the peak speedup is only about a
= 3.0 and happens at around 16 processors. This speedup is less than that predicted by Amdahl’s Law (a
= 5). Note that you can ...
You
ha
ve parallelized your serial application
,
but as you use more cores you are
n
o
t seeing any improvement
in performance
. What gives?
