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18%
Improved Performance with Parallel I/O
24.09.2015
Home »  HPC  »  Articles  » 
that is 80% parallelizable (20% is serial, primarily because of I/O). For one process, the wall clock time is assumed to be 1,000 seconds, which means that 200 seconds is the serial portion of the application
18%
System Logging for Data-Based Answers
25.01.2018
Home »  HPC  »  Articles  » 
2,400 lines of stats (one for each core). If you have 100 nodes, in one minute you have gathered 24,000 lines of stats for the cluster. In one day, this is 34,560,000 lines of stats for the 100 nodes
18%
Why Good Applications Don’t Scale
13.10.2020
Home »  HPC  »  Articles  » 
be parallelized). For one process, the wall clock time is assumed to be 1,000 seconds, which means that 200 seconds of the wall clock time is the serial portion of the application. From Amdahl’s Law, the minimum
18%
What is an IOPS Really?
24.02.2022
Home »  HPC  »  Articles  » 
B? Most of the time, IOPS are reported as a plain number (e.g., 100,000). Because IOPS has no standard definition, the number is meaningless because it does not define the payload size. However, over time
18%
Scalable mail storage with Dovecot and Amazon S3
10.04.2015
Home »  Archive  »  2015  »  Issue 26: OpenS...  » 
Lead Image © Vlad Kochelaevskiy, Fotolia.com
EUR5,000 per year for 10,000 mailboxes. Admittedly, that is not exactly cheap, but the number has little meaning. Figure 1: The license for the S3 plugin
18%
Why Good Applications Don't Scale
02.02.2021
Home »  Archive  »  2021  »  Issue 61: Secur...  » 
Lead Image © man64, 123RF.com
cannot be parallelized). For one process, the wall clock time is assumed to be 1,000 seconds, which means that 200 seconds of the wall clock time is the serial portion of the application. From Amdahl's Law
18%
Unleashing Accelerated Speeds with RAM Drives
02.08.2021
Home »  Archive  »  2021  »  Issue 64: Bare...  » 
Lead Image © Vladimir Nenov, 123RF.com
/write): rd0: ios=0/0, merge=0/0, ticks=0/0, in_queue=0, util=0.00% You will observe similar results with random read operations (Listings 6 and 7). The HDD produces about 2.5MBps, whereas the RAM drive
18%
Top Top-Like Tools
07.10.2014
Home »  Archive  »  2014  »  Issue 23: 10 Ti...  » 
of swap space (1,986,000KB, or about 2GB), the amount of swap space used (0KB), the amount of swap space free (1,986,000KB, or about 2GB), and the amount of cached memory used (942660KB, or about 1GB
18%
Rancher manages lean Kubernetes workloads
20.06.2022
Home »  Archive  »  2022  »  Issue 69: Terra...  » 
Lead Image © Sebastian Duda, 123RF.com
setups. Rancher itself states that a machine of this dimension can meaningfully run 2,000 clusters and up to 20,000 compute nodes, even with the database belonging to Rancher grabbing two cores and 4GB
18%
Monitoring in the Google Cloud Platform
20.06.2022
Home »  Archive  »  2022  »  Issue 69: Terra...  » 
Lead Image © Maksym Chornii, 123rf.com
1,000th call throws an error. To set up service monitoring, go to the left-hand menu in the GPC GUI and select Operations | Monitoring | Services . You will immediately notice that the App Engine

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