26%
    
    
    06.10.2022
        
    
    	
        , which is passed by the caller in CPU register rax
 on x86-64 machines [8]. Syscall arguments are passed in registers rdi
, rsi
, rdx
, r10
, r8
, and r9
. The return value of the syscall is returned
    
 
		    
				        
    26%
    
    
    14.08.2020
        
    
    	
         Capability
# smartctl -i /dev/sda
smartctl 7.2 2020-07-11 r5076 [x86_64-linux-5.4.0-42-generic] (CircleCI)
Copyright (C) 2002-20, Bruce Allen, Christian Franke, www.smartmontools.org
=== START
    
 
		    
				        
    26%
    
    
    29.09.2020
        
    
    	
        , use the -P show option (Listing 2).
Listing 2
Device Details
# smartctl -P show /dev/sda
smartctl 7.2 2020-07-11 r5076 [x86_64-linux-5.4.0-42-generic] (CircleCI)
Copyright (C) 2002-20
    
 
		    
				        
    25%
    
    
    02.08.2021
        
    
    	
        ).
Listing 4
smartctl on SAS Drive
$ sudo smartctl -a /dev/sdc
smartctl 7.1 2019-12-30 r5022 [x86_64-linux-5.4.0-66-generic] (local build)
Copyright (C) 2002-19, Bruce Allen, Christian Franke, www
    
 
		    
				        
    25%
    
    
    17.02.2015
        
    
    	
        _axs", "period"], {"semaj_axs":{"$lt":100}})
12 x_lab = "Semi-major axis / [AU]"
13 x_vals = ro.FloatVector([x**3 for x in rep.df.rx2(1)])
14
15 y_lab = "Orbital Period / [Years]"
16 y_vals = ro.FloatVector([x**2
    
 
		    
				        
    25%
    
    
    12.05.2021
        
    
    	
        .M.A.R.T.), you can use the smartmontools
 package and, again, more specifically, the smartctl
 binary (Listing 4).
Listing 4: smartctl
 on SAS Drive
$ sudo smartctl -a /dev/sdc
smartctl 7.1 2019-12-30 r5022 [x86
    
 
		    
				        
    25%
    
    
    07.04.2022
        
    
    	
        ,BROADCAST,RUNNING,MULTICAST>  mtu 1460
        inet 10.0.0.2  netmask 255.255.255.255  broadcast 0.0.0.0
        inet6 fe80::bfd3:1a4b:f76b:872a  prefixlen 64  scopeid 0x20
        ether 42:01:0a:80:00:02  txqueuelen 1000
    
 
		    
				        
    25%
    
    
    01.06.2024
        
    
    	
         is 20x because only 95 percent of the algorithm can execute in parallel (compute the fraction 1/20 from that 5% number). That limitation led to a search for embarrassingly parallel
 algorithms
    
 
		    
				        
    25%
    
    
    24.02.2022
        
    
    	
        .255.255.255  broadcast 0.0.0.0
        inet6 fe80::bfd3:1a4b:f76b:872a  prefixlen 64  scopeid 0x20
        ether 42:01:0a:80:00:02  txqueuelen 1000  (Ethernet)
        RX packets 11919  bytes 61663030 (58.8 Mi
    
 
		    
				        
    25%
    
    
    30.11.2020
        
    
    	
        ):
11
12   s = 0.0
13   s += h * f(a)
14   for i in range(1, n):
15     s += 2.0 * h * f(a + i*h)
16   # end for
17   s += h * f(b)
18   return (s/2.)
19 # end def
20
21
22 # Main section
23 comm = MPI