68%
15.06.2016
of time the NFS client waits on the NFS server before retransmitting a packet (no ACK received). The value for timeo
is given in tenths of a second, so if timeo
is 5
, the NFS client will wait 0.5 seconds
68%
20.06.2012
is to find out whether it runs on the master node when it is booted by using the chkconfig
command:
[root@test1 etc]# chkconfig --list
...
nfs 0:off 1:off 2:off 3:off 4:off 5:off 6
68%
02.08.2021
that enforces manual unlocking and long, complex passwords (Listing 1).
Listing 1
Enforcing Complex Passwords
New-ADFineGrainedPasswordPolicy -Name "HighSecServiceAccountsPolicy" -Precedence 500
68%
08.01.2013
_LOCAL_MACHINE\System\CurrentControlSet\Services\LanManWorkstation\Parameters]
DWORD DomainCompatibilityMode 1
DWORD DNSNameResolutionRequired 0
The preceding code tells the registry to add two DWORD
68%
24.09.2015
several aspects. First, the filesystem should have the ability to keep up as parallelism increases. For the file-per-process pattern, if each TP performs I/O at a rate of 500MBps, then with four TPs
68%
21.04.2016
. In the TOP500 list of November 2015, Linux accounted for 98.8% of the systems. I would call this a pretty dominating position; yet, many of the developers writing HPC software on Linux are unknown.
Gregory M
68%
15.08.2016
-performance computing (HPC). In the TOP500 list of November 2015, Linux accounted for 98.8 percent of the systems. I would call this a pretty dominating position; yet, many of the developers writing HPC software on Linux
67%
11.02.2016
version, the project offers two extremely lean ISO images. Our test team took a look at version 9.0, which is based on the now obsolete CentOS 6.5. The current version 9.1 is based on CentOS 6.7.
Even
66%
20.06.2022
!), and requires at least Windows Server 2012 R2 and PowerShell 2.0. Listing 1 shows the first lines of the migration loop.
Listing 1
Migration by Script
01 foreach ($Mailbox in (Get-Mailbox)) {
02
66%
04.08.2020
','josh').outE('created').inV().values('name').path()
==>[v[4],e[10][4-created->5],v[5],ripple]
==>[v[4],e[11][4-created->3],v[3],lop]
gremlin> g.V().outE('created').has('weight', 1.0).inV().values('name')
==>ripple
gremlin> g
