51%
17.03.2020
:
$ cat /proc/partitions|grep nvme
259 0 244198584 nvme0n1
259 3 97654784 nvme0n1p1
259 4 96679936 nvme0n1p2
I will be using partition 1 for the L2ARC read cache, so to enable
51%
21.08.2012
just two nodes: test1, which is the master node, and n0001, which is the first compute node):
[laytonjb@test1 ~]$ pdsh -w test1,n0001 uptime
test1: 18:57:17 up 2:40, 5 users, load average: 0.00, 0
50%
08.06.2021
properties:
CPU: Intel(R) Core(TM) i5-10300H CPU @2.50GHz
Processor base frequency: 2.5GHz
Max turbo frequency: 4.5GHz
Cache: 8MB
Four cores (eight with hyperthread)
45W thermal design
50%
10.11.2021
a directory
-v
or -vv
creates verbose output
-b
uses bzip2
compression
-g
uses gzip
compression
-l
uses lzo
compression
-L
n
uses compression level n
(1
-9
, with 7
being the default
50%
06.10.2019
, Splint [9] for C offers thorough code analysis. Listing 2 shows a deliberately broken sample program. The potential buffer overflow in line 8 and the format string vulnerability in line 9 are even
50%
23.03.2022
20 2020 openmpi-4.0.5.tar.gz
39322319 drwxrwxr-x 7 laytonjb laytonjb 4096 Oct 24 2020 psutil-release-5.7.3
32639755 drwxrwxr-x 2 laytonjb laytonjb 4096 Nov 6 10:25 pxz-master
31866302
50%
12.09.2013
;
05
06 print "Status: 200\nContent-Type: text/plain\n\n";
07 $|=1; $|=0; # flush
08
09 my $dbh=DBI->connect('dbi:Pg:dbname=r2', 'ipp', undef, {RaiseError=>1});
10
11 my $sth
50%
20.03.2014
to the minimum file allocation size a filesystem manages and effectively represent the smallest possible disk allocation for a file. (A smaller file would be padded with slack space to that minimum allocation
50%
18.03.2020
2 hours ago 9.83GB
49cbd14ae32f 3 hours ago 269MB
ubuntu 18.04 72300a873c2c 3 weeks ago 64.2MB
50%
06.10.2022
rd_size=524288
root@focal:~# ls /dev/ram0
/dev/ram0
root@focal:~# fallocate -l 2M header.img
root@focal:~# echo -n "not a secure passphrase" | cryptsetup luksFormat -q /dev/ram0 --header header
