51%
30.11.2025
, appearing in alphabetical order but allowing intervening letters, you can use the search expression:
"a.*e.*i.*o.*u"
This would match lines 1, 2, and 3. If you want lines containing all five vowels in order
51%
01.08.2019
exists, renaming the old one with ID sha256: f09fe80eb0e75e97b04b9dfb065ac3fda37a8fac0161f42fca1e6fe4d0977c80 to empty string
Loaded image: nginx:latest
With the docker images command, you can see
51%
14.03.2013
command:
# sockstat | grep "\*:[0-9]"
The description for rc.conf(5) lists the services that need to be bound to a fixed IP address via parameters. One example is the inetd service:
inetd_flags="-wW -a
51%
30.11.2025
and modifying the IP address in line 8. The line
lxc-create -n guest -f /lxc/conf.guest
Listing 3
Container Configuration: conf.guest
01 lxc.utsname = guest
02 lxc.tty = 4
03 lxc
51%
14.08.2017
to manage them disappeared.
Container Linux ruthlessly replaces the entire /usr directory instead of individual files (Figure 3). The main work is handled by Linux containers à la Docker [20], or Rkt [21
51%
19.06.2023
object
O
Python object
A simple example from nkmk creates a float64
data type (64-bit floating-point number):
import numpy as np
a = np.array([1, 2, 3], dtype=np.float64
50%
05.08.2024
/bin/ksh'
user_gecos: 'AIX guest user'
user_pgrp: 'staff'
user_groups: 'staff'
user_fsize: '-1'
user_passwd: "{ssha256}06$FkFHd0q1hxVonC2a$sa1WA0G3mPNWtz2GAhUkfcQ7BkD/mNngBu0Tn2.N.cl"
collections
50%
09.12.2019
to check follows
a, b = 1,2
c = a + b
# Code to check ends
end_time = time.time()
time_taken = (end_time- start_time)
print(" Time taken in seconds: {0} s").format(time_taken_in_micro)
If a section of code
50%
30.11.2025
); i+= 4096) newblock[i] = 'Y';
12 printf("Allocated %d MB\n", allocation);
13 }
14 }
Things are more interesting when memory is being used. Uncommenting line 11 does just that. The OOM
50%
28.07.2025
[i] + b[i];
}
When the number of cycles is known at compile time, a loop can be fully unrolled:
c[0] = a[0] + b[0];
c[1] = a[1] + b[1];
c[2] = a[2] + b[2];
c[3] = a[3] + b[3];
However, it remains