17%
06.05.2024
, including HPC, as you can see with the Compute Blade (Figure 3). Ivan Kuleshov had started work on CM4-based carrier boards designed to fit in standard rack structures (1U), and he created a
17%
10.06.2014
",
22 "description": "public"
23 }
24 ],
25 "ssh_key": true
26 },
27 "disk_driver": "virtio",
28 "nic_driver": "virtio",
29 "uuid": "555793a9-3c32-4eb9-ae81-f
17%
25.03.2020
"
Finally, you're ready to install your agent with a command that pulls in your environment variables:
$ curl -sfL https://get.k3s.io | K3S_URL=https://${MASTER}:6443 K3S_TOKEN=${TOKEN} sh -
In Listing 9 ... The k3s lightweight and secure Kubernetes distribution can handle both unattended workloads in remote locations with minimal resources and clusters of IoT appliances. ... Kubernetes k3s lightweight distro
17%
06.10.2019
.e., output all warnings) shows in Listing 4.
Listing 3
Splint Warnings
splint -strict example1.c
Splint 3.1.2 --- 11 May 2019
example1.c: (in function main)
example1.c:9:5: Format string
17%
10.04.2015
; Figure 3) [6], and Project Atomic, "a lean and mean OS built for containers" [7] looks promising, despite the beta state. If you want to dive deeper into the underlying technology, the OpenShift blog
17%
04.08.2020
->tv_nsec) * 1E-9;
24 }
25
26 int main(int argc, char* argv[argc+1]) {
27 if (argc < 2) {
28 fprintf(stderr, "Usage: %s NNN, NNN iterations\n",
29 argv[0]);
30 return EXIT_FAILURE;
31 }
32
17%
22.12.2017
in cs us sy id wa st
04 1 0 0 5279852 2256 668972 0 0 1724 25 965 1042 17 9 71 2 0
05 1 0 0 5269008 2256 669004 0 0 0 0 2667 1679 28 3 69 0 0
06 1 0
17%
21.08.2014
't connect to $remote_host:$remote_port: $@ \n";
17
18
19 while() {
20 my @lavg = Sys::CpuLoad::load();
21 my $ts=time();
22 print $socket "system.loadavg_1min $lavg[0] $ts\n";
23 print $socket "system ... 22
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01.06.2024
Running kube-proxy 1 5bf2de2a3af3c kube-proxy-b65c9
The mitigations for the above technique could be used to ensure that no containers mount docker
17%
26.02.2014
def
#
# Routine to add commas to a float string
#
def commify3(amount):
amount = str(amount)
amount = amount[::-1]
amount = re.sub(r"(\d\d\d)(?=\d)(?!\d*\.)", r"\1,", amount)
return amount[::-1