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18%
Have a Bash with the Zing network utility
25.09.2023
Home »  Archive  »  2023  »  Issue 77: Secur...  » 
Photo by Micah Tindell on Unsplash
: 55 ms. Port: 80: op 2.1. 10.0.0.23 80 Time: 26 ms. Port: 80: op 2.2. 10.0.0.23 80 Time: 56 ms. Port: 80: op 3.1. 10.0.0.23 80 Time: 25 ms. Port: 80: op 3.2. 10.0.0.23 80 Time: 48 ms. Port: 80: op 4
18%
Modern Fortran – Part 3
25.01.2017
Home »  HPC  »  Articles  » 
) :: a[*]    ! Array coarray   real, dimension(n), codimension[*] :: a   ! Array coarray   integer :: cx[10,10,*]   ! scalar coarray with corank of 3   ! Array coarray with corank of 3 with different cobounds real :: c(m,n) :: [0 ... Modern Fortran – Part 3
18%
Managing Cluster Software Packages
12.02.2013
Home »  HPC  »  Articles  » 
Modulefiles: 1) fftw/3.3.2/gnu4 2) mpich2/1.4.1p1/gnu4 $ ssh n0 $ module list Currently Loaded Modulefiles: 1) fftw/3.3.2/gnu4 2) mpich2/1.4.1p1/gnu4 $ exit $ export NOMODULES=1 $ ssh n0 $ module list
18%
Tools to Manage Storage
03.02.2024
Home »  HPC  »  Articles  » 
                                938G  718G  173G  81% /home /dev/nvme0n1p1                                511M  6.1M  505M   2% /boot/efi /dev/sda1                                     5.5T  3.1T  2.1T  60% /home2 192.168.4.100:/home
18%
Why Good Applications Don’t Scale
13.10.2020
Home »  HPC  »  Articles  » 
You ha ve parallelized your serial application ,  but as you use more cores you are  n o t seeing any improvement  in performance . What gives? ... , a is the application speedup, n is the number of processors, and p is the “parallel fraction” of the application (i.e., the fraction of the application that is parallelizable), ranging from 0 to 1. Equations are nice ... You  ha ve parallelized your serial application ,  but as you use more cores you are  n o t seeing any improvement  in performance . What gives?
18%
Failure to Scale
03.07.2013
Home »  HPC  »  Articles  » 
speedup, n is the number of processors, and p is the parallel fraction, or the fraction of the application that is parallelizable (0 to 1). In an absolutely perfect world, the parallelizable fraction
18%
Pre-authentication for Kerberos services
04.04.2023
Home »  Archive  »  2023  »  Issue 74: The F...  » 
Photo by pina messina on Unsplash
. For practical use, you first need to call kinit with the -n option to give you an anonymous TGT: kinit -n klist Ticket cache: KCM:0 Default principal: WELLKNOWN/ANONYMOUS@WELLKNOWN:ANONYMOUS [...] You can now
18%
History and use of the mail utility
05.12.2014
Home »  Archive  »  2014  »  Issue 24: Visua...  » 
Lead Image © Vlad Kochelaevskiy, fotolia.com
[<-] 334 VXNlcm5hbWU6 [->] Y2hyaXNiaW5uaWUzQGdtYWlsLmNvbQ== [<-] 334 UGFzc3dvcmQ6 [<-] 235 2.7.0 Accepted [->] MAIL FROM: [<-] 250 2.1.0 OK t2fjm4427fd213ply.2523 - gsmtp [->] RCPT TO
18%
Virtualization with KVM
29.06.2011
Home »  CloudAge  »  Articles  » 
 
than 0 (Figure 3). If not, either the processor doesn't support the special commands, or the commands have been disabled in the computer's BIOS. Users with Intel processors can additionally check
18%
Graphite: Collect and Visualize Numeric Data
30.07.2014
Home »  HPC  »  Articles  » 
 => SOCK_STREAM)     or die "Couldn't connect to $remote_host:$remote_port: $@ \n";     while() {  my @lavg = Sys::CpuLoad::load();  my $ts=time();  print $socket "system.loadavg_1min $lavg[0] $ts\n";  print

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