19%
10.06.2015
to the first sed I know that here is only a SINGLE space
45 display_list="$(sed ':a;N;$!ba;s/\n / /g'<<<"$xrandr_current" | sed \
-n -e 's/^\([a-zA-Z0-9_-]\+\) connected.* \([0-9]\+\)mm.* \([0-9]\+\)mm
19%
15.12.2016
are over i
= 2,n
− 1 and j
= 2,n
−1. Here is how you can write the iteration over the domain using array notation:
a(2:n-1,2:n-1) = 0.25 * &
(a(1:n-2,2:n) + a(3:n,2:n) + a(2:n,1:n-2) + a(2:n,3:n
19%
13.04.2023
Interactive HPC applications written in languages such as Python play a very important part today in high-performance computing. We look at how to run Python and Jupyter notebooks on a Warewulf 4 ... -*-
--------------------------------------------------------------------------------
-- Anaconda (Python) (Version 22.9.0 Python 3.9.13 (main, Aug 25 2022, 23:26:10)
--------------------------------------------------------------------------------
help(
[[
This module loads Anaconda so you can
19%
02.06.2020
cddaa6-0886-44b3-9590-16717d5cd3c2",
20 "service_instance_guid": null,
21 "port": null,
22 "domain_url": "/v2/shared_domains/fb6bd89f-2ed9-49d4-9ad1-97951a573135",
23
19%
30.01.2024
Dell Precision Workstation T7910
Power
1,300W
CPU
2x Intel Xeon Gold E5-2699 V4, 22 cores, 2.4GHz, 55MB of cache, LGA 2011-3
GPU, NPU
n/a*
Memory
18%
06.10.2019
://creativecommons.org/licenses/by-sa/3.0/
Splint: http://splint.org
Hoare, C.A.R. An axiomatic basis for computer programming. Communications of the ACM
, 1969;12(10):576-583, https://web.archive.org/web/20160304013345/http
18%
17.01.2023
x86_64 2.9.1-9.el8 baseos 393 k
groff-base x86_64 1.22.3-18.el8 baseos 1.0 M
hwloc-ohpc x86_64 2.7.0-3.9
18%
04.04.2023
x86_64 2.9.1-9.el8 baseos 393 k
groff-base x86_64 1.22.3-18.el8 baseos 1.0 M
hwloc-ohpc x86_64 2.7.0-3.9
18%
25.03.2021
-machine)
UUID : e0e5d514:d2294825:45d9f09c:db485a0c
Events : 3
Number Major Minor RaidDevice State
0 252 0 0 active sync /dev/rd0
1 8 34
18%
02.08.2021
SGEMM
for N = [2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192]
A = single( rand(N,N) );
B = single( rand(N,N) );
start = clock();
C = A*B;
elapsedTime = etime(clock(), start